a) calculate the height (in m) of a cliff if it takes
2.19 s for a rock to hit the ground when it is thrown straight up
from the cliff with an initial velocity of 8.03 m/s.
b) How long (in s) would it take to reach the ground if it is
thrown straight down with the same speed?
a] Using the second equation of motion,
H = ut + 0.5gt^2
= -8.03*2.19 + 0.5*9.8*2.19^2
= 5.915 m
b] Using the second equation of motion,
5.915 = 8.03*t + 0.5*9.8*t^2
t = 0.551 s
a) calculate the height (in m) of a cliff if it takes 2.19 s for a...
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