Question

A golf ball (50 g) hit by a club is accelerated from rest to 50 m/s in 2.50 ms. What are the magnitudes of the impulse delive

0 0
Add a comment Improve this question Transcribed image text
Answer #1

feel free to drop comment if you have any doubt. first question of the image posted is being answered here.

acceleration of the ball = 5o - o 2.5x103 G = 20000 mg average = ma = 50x10 3 x 20000 = 1000 W/ansmes. Impulse = faverage xt

Add a comment
Know the answer?
Add Answer to:
A golf ball (50 g) hit by a club is accelerated from rest to 50 m/s...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • questions 4 and 5 please 4. A 1.50 kg point mass is 200.0 cm from a...

    questions 4 and 5 please 4. A 1.50 kg point mass is 200.0 cm from a 3.00 kg point mass. Where is their center of mass, measured from the 1.50 kg mass? Xcm =- 5. Starting from rest, a disk spins with a constant angular acceleration. After 2 minutes it has completed 50 revolutions. How many revolutions will it have completed at 4 minutes? a) 25 rev b) 71 rev. c) 100 rev d) 200 rev

  • 4. A 1.50 kg point mass is 200.0 cm from a 3.00 kg point mass. Where...

    4. A 1.50 kg point mass is 200.0 cm from a 3.00 kg point mass. Where is their center of mass, measured from the 1.50 kg mass? Xcm = 5. Starting from rest, a disk spins with a constant angular acceleration. After 2 minutes it has completed 50 revolutions. How many revolutions will it have completed at 4 minutes? a) 25 rev b) 71 rev c) 100 rev d) 200 rev /25

  • number 2 and 3 please 2. A disk of radius 10.0 cm spins about an axis...

    number 2 and 3 please 2. A disk of radius 10.0 cm spins about an axis through its center at a constant 5.0 rad/s. What is the linear velocity, centripetal and tangential accelerations of a point on its rim? linear velocity = centripetal acceleration = tangential acceleration = 3. Under what conditions is the linear momentum of a system conserved? (Do not state when the initial is equal to the final.)

  • A 5 kg ball traveling to the right at 5 m/s collides with a 4 kg...

    A 5 kg ball traveling to the right at 5 m/s collides with a 4 kg ball at rest. After the collision, the 4 kg ball is traveling to the right at 5.556 m/s. What is the velocity of the ball on the left after the collision? A motor spins a disk (Idisk = 24.4 kg*m2) with a torque of 39 N*m, and a 10 N frictional force acts on the disk at a radius of 2 m. Attached to...

  • A hammer thrower accelerates the hammer (mass = 7.30 kg) from rest within four full turns...

    A hammer thrower accelerates the hammer (mass = 7.30 kg) from rest within four full turns (revolutions) and releases it at a speed of 27.7 m/s A.) Assuming a uniform rate of increase in angular velocity and a horizontal circular path of radius 1.30 m , calculate the angular acceleration. B.) Calculate the (linear) tangential acceleration. C.) Calculate the centripetal acceleration just before release. D.) Calculate the net force being exerted on the hammer by the athlete just before release....

  • (a) What is the tangential acceleration of a bug on the rim of a 6.0 in, diameter disk if the disk moves from rest...

    (a) What is the tangential acceleration of a bug on the rim of a 6.0 in, diameter disk if the disk moves from rest to an angular speed of 79 rev/min in 5.0 s? 425 Your response differs from the correct answer by more than 100%, m/ s (b) When the disk is at its final speed, what is the tangential velocity of the bug? m/s (c) One second after the bug starts from rest, what is its tangential acceleration?...

  • A 39.2-cm diameter disk rotates with a constant angular acceleration of 2.8 rad/s2. It starts from rest at t = 0, a...

    A 39.2-cm diameter disk rotates with a constant angular acceleration of 2.8 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time. (a) Find the angular speed of the wheel at t 2.30 s. rad/s 2.30 s (b) Find the linear velocity and tangential acceleration of P at t...

  • A large metal disk with mass M=5 kg and R= 3m starts from rest and is...

    A large metal disk with mass M=5 kg and R= 3m starts from rest and is free to without friction about an axis passing through its center of mass point 0. perpendicular to the disk. 4 light engines providing a constant thrust force F=20 N, are connected to the circumforce of the disk in the orientation shown. dashed lines are tangent to the disk. Engines ignite at t=0. The moment of inertia of the disk about its center I disk=...

  • (a) What is the tangential acceleration of a bug on the rim of a 6.0 in diameter disk if the disk moves from rest t...

    (a) What is the tangential acceleration of a bug on the rim of a 6.0 in diameter disk if the disk moves from rest to an angular speed of 79 rev/min in 5.0 s? 120 m/s? (b) When the disk is at its final speed, what is the tangential velocity of the bug? 630 m/s (c) One second after the bug starts from rest, what is its tangential acceleration? 126 m/s? What is its centripetal acceleration? 2083 m/s2 What is...

  • 3. A disk 6.0cm in diameter and moment of inertia of 0.015kg-m’ initially at rest at...

    3. A disk 6.0cm in diameter and moment of inertia of 0.015kg-m’ initially at rest at t = 0, is spun up to 720-rpm over 6.0s about an axis through its center of mass. Assume the angular acceleration is constant. a) Find the angular velocity (rad/s) at 6.0s b) Find the angular acceleration (rad/s) c) Find the number of revolutions the disk spins through during that interval. d) What is the mass of the disk? e) What is the change...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT