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questions 4 and 5 please
4. A 1.50 kg point mass is 200.0 cm from a 3.00 kg point mass. Where is their center of mass, measured from the 1.50 kg mass?
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Answer #1

4)

suppose 1.5 kg is sitting at ( 0, 0) and 3 kg is sitting at ( 200 , 0 ) so

X_com = ( 1.5 *0 + 3*200 )/ (3+1.5) =133.333333 cm

so COM is 133.33 cm away from 1.5 kg mass

5)

θ = ωi*t +1/2*α*t^2

50 *2pi =0 +0.5*α*120^2

α = 50 *2pi /( 0.5*120^2) =0.0436332313 rad/s2

speed at 120 sec

v = u +at = 0 + 0.0436332313*120 = 5.23598776 rad/s

θ = ωi*t +1/2*α*t^2

θ = 5.23598776*120 + 1/2*0.0436332313*120^2 =

= 942.47779656 rad

no. of revolution =942.47779656/(2pi) = 150

so total revolution = 200

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