Homework Answers
distance between cnetr to proton, d = r + h
= (d/2) + h
= 6/2 + 5
= 8fm
= 8*10^-15 m
a) F = k*Q*q/d^2
= 9*10^9*54*1.6*10^-19*1.6*10^-19/(8*10^-15)^2
= 194.4 N
b) a = F/m
= (194.4/1.67*10^-27)
= 1.16*10^29 m/s^2
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PHY2054 - Physics 2 -Spring 2019 Hi SamirSign Out Help sics HW 2: Ch 20 47...
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