Question

ReviewI Constants The nucleus of a 12 Xe atom (an isotope of the element xenon which has a total of 125 protons and neutrons) is 6.0 fm in diameter. (1 fm = 1 femtometer = 1 × 10-15 m) Xenon has 54 protons, therfore, the nucleus has total charge q = +54e. Another proton (which is not part of the Xenon nucleus) is placed a distance d 9.0 fm from the surface of the nucleus. (Figure 1)

Answer 1

Magnetic of electric force on the proton Vertical-bar F^vector Vertical-bar = -9 times 10^9 times (54 times 1.6 times 10^-19) times (1.6 times 10^-19) /nucleus size + distance of nucleus and proton)^2 = -(9 times 10^9) times (54 times 1.6 times 10^-19) times (1.6 times 10^-19)]/(6 times 10^-15 + 9 times 10^-15)^2 = -[1244.16 times 10^-29] /(15 times 10^-15)^2 = -1244.16 times 10^-29/225 times 10^-30 = -5.5296 times 10 Vertical-bar F^vector Vertical-bar = -55.296 N The negative shows the attractive nature of the force m = proton mass m a = 55.296 or a = 55.296/1.672 times 10^-27 Acceleration, a = 33.07 times 10^27 m/sec^2