In the specific heat capacity experiment, the unknown object has a mass of 0.085 kg and was cooled to -6C. Then, it was placed in a calorimeter (mcalorimeter = 0.12 kg) that contain water (mwarter = 0.27 kg) at a temperature of 28 oC. After 5 minutes the temperature dropped to 23C. Determine the heat lost by the calorimeter. (cwater = 4186 J/kg. oC and ccalorimeter = 900 J/kg. oC)
In the specific heat capacity experiment, the unknown object has a mass of 0.085 kg and...
In the specific heat capacity experiment, the unknown object has a mass of 0.070 kg and was cooled to -3C. Then, it was placed in a calorimeter (mcalorimeter = 0.13 kg) that contain water (mwarter = 0.26 kg) at a temperature of 26 oC. After 5 minutes the temperature dropped to 24C. Determine the heat lost by the water. (cwater = 4186 J/kg. C and ccalorimeter = 900 J/kg. C)
In the specific heat capacity experiment, the unknown object has a mass of 0.058 kg and was cooled to -5 oC. Then, it was placed in a calorimeter (mcalorimeter = 0.12 kg) that contain water (mwarter = 0.22 kg) at a temperature of 28 C. After 5 minutes the temperature dropped to 23 oC. Determine the heat gained by the unknown object. (cwater = 4186 J/kg. C and ccalorimeter = 900 J/kg. C)
In the specific heat capacity experiment, the unknown object has a mass of 0.073 kg and was cooled to -9 C. Then, it was placed in a calorimeter (mcalorimeter = 0.11 kg) that contain water (mwarter = 0.23 kg) at a temperature of 26 C. After 5 minutes the temperature dropped to 22.4 C. Determine the specific heat capacity of the unknown object. (cwater = 4186 J/kg. C and ccalorimeter = 900 J/kg. C)
In the specific heat capacity experiment, the unknown object was cooled, then placed in a calorimeter that contain water. The temperature of the calorimeter and water was measured using a temperature probe. The data was fitted using natural exponent function: 20.3+(24.7-20.3) exp(-t/0.51) Determine the ambient temperature.
In the specific heat capacity experiment, the unknown object was cooled, then placed in a calorimeter that contains water. The temperature of the calorimeter and water was measured using a temperature probe. The data was fitted using natural exponent function: 20.9+(22.9-20.9) exp(-t/0.66) Determine the initial temperature of the calorimeter and water mixture.
A 25.0-g block of ice at -15.00°C is dropped into a calorimeter (of negligible heat capacity) containing water at 15.00°C. When equilibrium is reached, the final temperature is 8.00°C. How much water did the calorimeter contain initially? The specific heat of ice is 2090 J/kg ∙ K, that of water is 4186 J/kg ∙ K, and the latent heat of fusion of water is 33.5 × 104 J/kg.
An unknown metal sample of 54 g at 108°C is dropped into a calorimeter cup containing 190 g of 2. water at 20.3°c. After equilibrium is reached, the temperature of water is increased to 24.6°C. What is the specific heat of this metal? identify the metal by looking up the specific heat table. (Specific heat of water is 4186 J/kg.°C and heat capacity of the calorimeter is 125 J/oC)
In an experiment to measure the specific heat capacity of aluminium, identical size copper and aluminium blocks were alternately placed in an insulated calorimeter and heated by an electrical heater. The electrical heater supplied an identical energy E to the metal blocks. It was assumed that the heat loss (h) from both calorimeter measurements was identical. The measured masses were 530 g for the aluminium block and 1700 g for the copper block. The temperature rises were 15.3oC for the...
4. What is the average specific heat capacity of the unknown metal in this experiment? 5. What is the unknown metal? Use Table 1 for reference. Table 2: Mass Mass (8) Water 49.2g Unknown Metal Strip 22.3g Table 3: Specific Heat Data Temperature (°C) Trial 1 Trial 2 Time (minutes) Trial 3 Initial 23 22.6 23.2 5 minutes 23.6 23.3 24.3 6 minutes 23.6 23.3 24.3 7 minutes 23.66 23.3 24.2 8 minutes 23.6 23.3 24.2 9 minutes 23.4 23.3...
6.21) Is the specific heat capacity of a substance an intensive or extensive property? Explain. 6.23) Calculate q when 0.10 g of ice is cooled from 10. °C to -75. °C. (S ice = 2.087 J/g•°C). 6.25) A 27.7 g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5 °C? (s of ethylene glycol = 2.42 J/g•°C) 6.27) One piece of...