3. Consider the following weak acids and their K, values, calculate the pK, for each acid. HC,H,O, - Acetic acid K. = 1.8 x 105 PK,= H,PO, - Phosphoric acid K = 7.1 x 10 PK, HCIO - Hypochlorous acid K = 3.5 x 10 pk = You want to prepare buffers at pH 2.8, 4.5 and 7.5. Which weak acid-conjugate base buffer system is the best choice for each pH from the acids listed? Write the reaction and indicate...
11. If a weak acid has a pK of 5, what is the ratio of [base]/[acid] at pH 5? 12. If a weak acid has a pK of 5, what is the ratio of [base|/[acid] at pH 4? 13. If a weak acid has a pK of 5, what is the ratio of [base]/[acid] at pH 6? 14. If a weak acid has a pK of 4 what the pH when the ratio of [base]/[acid] is 4? 15. If a...
NHz is a weak base (K) = 1.8 x 10 %) and so the salt NHCl acts as a weak acid. What is the pH of a solution that is 0.043 M in NH CI at 25°C? pH =
Acetic acid (HCH,O,) is a weak acid with K, = 1.8. 10 . The pH of a 0.500 M acetic acid is:
its
Ka not K9
The K, of a weak acid is 1.80 x 10-4. What is the pk of this acid? Place your answer in the box. Express your answer using only a number or numbers without text.
A weak acid has a Ka equal to 1.8 x 10-5. What is the % ionization of a 0.0115 M aqueous solution? Select one: o a. 0.045 O b. 0.040 o c.4.0 O d.3.3
5. The K of acetic acid is 1.7 x 10". What is the pk of acetic acid?
A weak acid has an initial concentration of 0.3 M (K = 1.3 x 10-7) A) Calculate (H) at equilibrium in molarity B) Calculate [OH-] at equilibrium in molarity C) Calculate pH of the solution D) % ionization of the acid
28. An initially 1.8 M aqueous solution of a weak monoprotic acid has a total ion concentration has a total ion concentration of 8.45 x 10-3 M when equilibrium is established. What is the acid-ionization constant, K of the weak acid? (assume n a. 3.3 x 10-2 b. 6.8 x 10-2 c. 1 x 10-5 d. 7.1 x 10-5 e. 2.7 x 100
6) At 25 C, the K, for formic acid (HCO2H) is 1.8 x 10-4. What is the pH of a 0.10 M aqueous solution of lithium formate (LiHCO2)? 7) What is the pH (aq., 25 °C) of this solution: adding 1.64 grams of sodium acetate to give 200.0 ml solution at 25.0°C? The K, at 25.0°C for acetic acid is 1.8 x 10-5.