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A hollow cylinder is released from rest and rolls down the incline without slipping. The incline...

A hollow cylinder is released from rest and rolls down the incline without slipping. The incline has an angle of thera=40 degrees with the horizontal. The mass and radius of the cylinder is M=5kg and R=0.55m respectively. Moment of inertia of a hollow cylinder is I=MR^2.
a)Draw the free body diagram of the hollow cylinder showing all the forces and their components.
b) Using newtons 2nd law for linear and rotational motion, derive an expression for linear acceleration of the center of the mass of the cylinder and calculate it. [ you need to use a=alphaR]
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Answer #1

m= mass of cylinder = 5kg migh- tmv t I w2 - I mort I may h-ssing (77 A2 te AL/ mkr I = MR =&mr(itt % = 225 yg & sino + (1

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