Homework Answers
a) Li (3) 1s22s1
For 2s1 the quantum numbers are n=2, l = 0, m= 0, s= +1/2
b) Br(35)becomes Br-(36)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6
So the last electron has
n= 4,l= +1, m= +1, s = -1/2
c)Cs has its last electron as 6s1 which is lost to become
Cs+
Its quantum numbers are
n=6, l=0, m=0 and s= +1/2
d) The highest energy electron in B atom is its last electron
B(5) has 1s2 2s2 2p1
thus 2p1 has
n=2, l=1. m= +1, s= +1/2
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Identify which sets of quantum numbers are valid for an
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Part B:
Thanks in advance! Any helpful explanation on how to do this
problem would also be appreciated.
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Part B:
Thanks in advance! Any helpful explanation on how to do this
problem would also be appreciated.
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