Question
Ayúdeme por favor solo me quedan 2 INTENTOS
6:25 p. m. Vie 25 ene. 58 %. oncapat.hep.uprm.edu Traveling Car Puntos:2 A car travels a certain distance along a straight road (in the +x direction). The distance the car travels as a function of time is shown in the figure below. When the car changes speed it does so uniformly. Select the appropriate choice for each statement 1000 E800 600 400 200 20 40 60 Time (s) Fase At 79 sec, the speed is as high as it gets. Greater than The acceleration magnitude at 37 sec is Greater thanThe x-acceleration is zero at 26 sec the acceleration magnitude at 15 sec. Greater than The speed at 10 sec is.. the speed at 79 sec. Equal to The speed is.. zero at 20 sec Equal to By extrapolating the straight sections of the graph, you can estimate the time during which the speed is changing. This, with the change in speed, shõuld let you estimate the magnitude of the acceleration The x-acceleration is zero at 15 sec Enviar Resquests Incorrecto. Tries 8/10 Intentos Anteriores Using the graph above, calculate the average speed of the car for the period from 0 to 20.0 s
6:27 p. m. Vie 25 ene. 58 % loncapat.hep.uprm.edu 1000 E 800 600 400 Less than 200 Vie, 25. Equal to En 2019, Greater Incorrecto. (Intento 1) New problem variation this try. 1:10:33 than Less than Less than 20 hs (AST) False Greater than Greater than At 79 sec, the speed The acceleration mag The x-acceleration is The speed at 10 sec The speed is.... zer False Greater than itude at 15 sec. Greater than Equal to Vie, 25. Equal to En 2019, Greater 2 Incorrecto. (Intento 2) Equal toThe x-acceleration is By extrapolating the straight se changing. This, with the change New problem variation this try. 7:30:10 than hs (AST) Less than Less than during which the speed is ide of the acceleration. Enviar RespuestaIncorrecto. Tries Using the graph above, calculate 1.50×101 m/s om 0 to 20.0s iCorrecto! Su recibo es 152-4673 Enviar Mensaje de Discusión Enviar Reacción
6:27 p. m. Vie 25 ene. 58 % . loncapat.hep.uprm.edu appropriate choice for each statement. 1000 E 800 600 than Greater than 400 Vie, 25. 200 3 Incorrecto. (Intento 3) incorecto. (Intento 3) En 2019,ualto 7:30:47 Greater hs (AST) than 20 than Less than Less than Greater Time At 79 sec, the speed The acceleration mag The x-acceleration is The speed at 10 sec The speed is... zer The x-acceleration is False Greater than Greater than Gresater han Equal to itude at 15 sec Vie, 25. than Incorrecto. (Intento 4) New probem variation this try. 9:11:47 En 2019, Equal to Greater hs (AST) than Equal to By extrapolating the straight se Equal to during which the speed is de of the acceleration changing. This, with the change Less 8 Enviar Respuesta Incorrecto. Tries Using the graph above, calculate the average speed of the car for the period from 0 to 20.0s 1.50x101 m/s Correcto! Su recibo es 152-4673 Intentos Anteriores
6:28 p. m. Vie 25 ene. 令58%. loncapat.hep.uprm.edu 1000 E 800 600 Greater than Greater 400 200 Vie, 25. En 2019, Equal to 14:13:12 Greater 6 Incorrecto. (Intento 6) 20 hs (AST) than Time to Less than Fabe At 79 sec, the speed Greater han The acceleration mag Greater han The x-acceleration is Greater than The speed at 10 sec Equal to The speed is ze Greateritude at 15 sec. than Greater Vie, 25. than 16:36:54 Greater o. (Intento 7) En 2019, False o The x-acceleration is Equal to hs (AST) than By extrapolating the straight se during which the speed is changing. This, with the change Enviar Resqusesta Incorrecto. Tries 8 Using the graph above, calculate 1.50x101 m/s Equal tode of the acceleration Less than om 0 to 20.0s Correcto! Su recibo es Enviar Mensaje de Discusión Enviar Reacción
6:28 p.m. Vie 25 ene. 58 % loncapat.hep.uprm.edu 1000 E 800 600 400 Greater than Greater 200 Vie, 25. than En 2019, False Incorrecto. (Intento 7) 16:36:54 Greater 20 hs (AST) than Time Less than At 79 sec, the speed The acceleration mag The x-acceleration i False Greater han tude at 15 sec. False Greater than Greater than Gresater than The speed at 10 sec Equal toThe speed is zer Vie, 25. Greater En 2019, than 18:20:25han hs (AST) Greater The x-acceleration is 8 Incorrecto. (Intento 8) Equal to By extrapolating the straight se during which the speed is de of the acceleration than Equal to Equal to changing. This, with the change Enviar Respuesta Incorrecto. Tries Using the graph above, calculate 1.50x101 m/s om 0 to 20.0 s Correcto! Su recibo es 152-4673 Enviar Mensaje de Discusión Enviar Reacción
6:28 p. m. Vie 25 ene. 令58 % . oncapa1.hep.uprm.edu 1000 E 800 600 Greater than Greater 400 200 Vie, 25. than En 2019, Equal to 4:13:12 Greater 6 Incorrecto. (Intento 6) 20 hs (AST) than Time to Less than Greater than Greater Fabe At 79 sec, the speed Greater than The acceleration mag Greater han The x-acceleration is Greater han The speed at 10 sec Equal to The speed is zer Equal toThe x-acceleration is By extrapolating the straight se changing. This, with the change itude at 15 sec. Vie, 25. than En 2019, False 16:36:54 Greater 7 Incorrecto. (Intento 7) hs (AST) than during which the speed is Equal tode of the acceleration Less than Enviar RespuestIncorrecto. Tries Using the graph above, calculate 1.50x101 m/s om 0 to 20.0 s Correcto! Su recibo es 152-4673 Enviar Mensaje de Discusión ¡¡Enviar Reacción
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