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After 0.600 L of Ar at 1.10 atm and 249°C is mixed with 0.200 L of O2 at 370 torr and 112°C in a 400.-mL flask at 23°C, what

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Answer #1

Pressure of Ar =P, = lloutm Temperature = T = 249°C - T = ( 249 + 273) K - Volume of Arl= = 522k o-GooL =V Pressure of 0₂1

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