can you please explain each answer 1. Give the number of lone pairs around the central...
) Give the number of lone pairs around the central atom and the molecular geometry of SCl2. A) O lone pairs, linear B) 3 lone pairs, bent C) 1 lone pair, bent D) 3 lone pairs, linear E) 2 lone pairs, bent
CHEM 1411. Review Exercises for Chapter 3, 7, 8. F19 1. Give the number of lone pairs around the central atom and the geometry of the ion CIO2 A) 0 lone pairs, linear 1 lone pair, bent B) C) 2 lone pairs, bent D) 3 lone pairs, bent E) 3 lone pairs, linear 2. Predict the geometry and polarity of the CS2 molecule. A) linear, polar B) linear, nonpolar C) tetrahedral, nonpolar D) bent, nonpolar E) bent, polar 3. Which...
Provide the correct molecular geometry for (a), given the number of lone pairs and bonding groups on the central atom. trigonal planar octahedral trigonal bipyramidal trigonal pyramidal square pyramidal tetrahedral seesaw bent linearProvide the correct molecular geometry for (b), given the number of lone pairs and bonding groups on the central atom. trigonal bipyramidal square pyramidal bent tetrahedral trigonal planar seesaw trigonal pyramidal octahedral linear Provide the correct molecular geometry for (c), given the number of lone pairs and bonding groups on the...
Predict the shape and polarity of each of the following molecules: A central atom with three identical bonded atoms and one lone pair. trigonal planar trigonal pyramidal bent (120°) linear tetrahedral bent (109) Submit Request Answer Part B A central atom with three identical bonded atoms and one lone pair nonpolar polar Submit Request Answer Part C A central atom with two bonded atoms and two lone pairs linear trigonal planar trigonal pyramidal bent (109) tetrahedral bent (120°) Submit Request...
Given the number of lone pairs around the central atom and the molecular geometry of XeF2. a. 0 lone pairs, linear b. 1 lone pair, bent c. 3 lone pairs, linear d. 2 lone pairs, bent
Draw the Lewis structure of XeCl. Include all lone pairs. Identify the molecular geometry of Xeci, Select Draw Rings More Erase trigonal pyramidal T-shaped square planar O tetrahedral O octahedral trigonal planar linear trigonal bipyramidal square pyramidal bent O see-saw What are the approximate bond angles in XeCl,? An XeCl, molecule is O polar O nonpolar. 109.5° 90° 120° 180°
Draw the Lewis structure of \(\mathrm{SF}_{4}\) showing all lone pairs.Identify the molecular geometry of \(\mathrm{SF}_{4}\).tetrahedralsee-sawlineartrigonal bipyramidalbentT-shapedtrigonal planartrigonal pyramidaloctahedralsquare planarsquare pyramidal$$ \begin{array}{l} \text { What is the hybridization of the central atom? }\\ s p^{3}\\ s p^{3} d^{2}\\ s p\\ s p^{2}\\ \text s p^{3} d \end{array} $$$$ \begin{array}{l} \text { What are the ideal bond angles of this geometry? }\\ 90^{\circ}\\ 109.5^{\circ}\\ 180^{\circ}\\ 120^{\circ} \end{array} $$An \(\mathrm{SF}_{4}\) molecule ispolar.nonpolar.
both questions please Indicate the geometry around each specified atom in the chemical shown Type in the following number to indicate the Geometry for each atom in the structure shown (You must type in the number for the geometry only otherwise the computer will not recognize your answer. Molecular Geometry 1 = Linear 2 = Bent (Trigonal) 3 Trigonal Planar 4 = Bent (Tetrahedral) 5-Pyramidal 6 = Tetrahedral 7 = Not a central atom 8 = No right answer i.e.,...
14 Which of the following is true if a molecule possesses lone pairs on the central atom but is not hydrogen bonded? (A) the molecule will have a hydrogen bonded directly to an N, O, or F (B) the molecule will be nonpolar (C) the molecule will be an ionic crystal lattice structure where there are strong clectrostatic (D) the molecule will be polar 15 A substance with strong intermolecular forces will have (A) low boiling point (B) high reactivity...
How many lone pairs if electrons are on the central atom of CHCl3 and what is the molecular shape? a) one, tetrahedral b) zero, tetrahedral c) zero, bent d) one, triginal planar e) one, trigonal pyramidal please explain your answer :)