Homework Answers
Given Information,
Our hypothesis is,
(Left tailed test)
1. Since, sample size is small
(n<30) and population standard deviation (
)
is unknown, so t-test is use here.
2. Test statistics:
Test statistics is 2.9167
The level of significance (
)
is not given in the problem, so if 
Degree of freedom = n-1 =25-1= 24
Therefore, critical t value at 0.05 level of significance for 24 degree of freedom is 1.711 (From t- table)
Since, calculated t is greater than the critical t value, i.e.,
,
.
Therefore, we conclude that there is enough evidence to support the claim that the women with ovarian cancer have fewer children than women in the general population in the same age group.
3. P- value: P value is calculated in R as:
(1-pt(2.9167,24)) = 0.00378
4. Conclusion: Since, p value is less than the specified level of significance, i.e.,
Therefore, we conclude that there is enough evidence to support the claim that the women with ovarian cancer have fewer children than women in the general population in the same age group.
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