Resistors R1 = 4on and R2 = 60Ω are connected series and the combination is parallel...

Question

Question

Answer 1

Answer #1

a)

Current flowing through R1 and R2

I₁₂=V₂/R₂ =10/60 =0.16667 A

Voltage across R1 is

V₁=I₁₂R₁ =0.16667*40 =6.6667 V

Voltage of the battery

V=10+6.6667 =16.6667 Volts

b)

Voltage across R3 is

V₃=V =16.6667 Volts

Current through R3 is

I₃=V/R₃=16.6667/36=0.463 A

Power dissipated in R3 is

P₃=I₃²R₃=0.463²*36=7.716 Watts

Answer 2

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