If there are 3 different chiral centers then we should get 23 = 8 number of stereoisomers. But here we'll get only four isomers. They are:
If you clearly see then you'll fing there is a plane of symmentry present in both 1 and 2, that is perpendicular to the plane of paper and passing through the mid carbon (Br containing). Due to this we lose two optical isomers, which if present, could be the enantiomer of these two.
In 3 and 4, for both the terminal chiral carbon configurations are same. For 3, it is R and for 4 it is S. So, Though the molecules are optically active and enantiomers to each other, the mid carbon becomes achirotopic. It's orientation becomes no longer considerable. So, again we lose two enantiomers for two orientations. What I am trying to say is depicted with the example of 3:
Both the molecules are same, we can get the other by just the rotation of one. So, the orientation of the mid carbon is not significant here.
There is no general rule on number of enantiomer and diastereomer. It totally depends on the nature of chiral centers. But you can always predict the toal number of possible stereoisomer.
what are all the isomers and is there any general rule ?? diasterisomers, enantioisomers ??
#7) Which of the following statements, if any, is or are true? As a general rule, income generated by property is not taxable to the person who owns the property if the income is paid to directly to another person who, prior to such payment, performed services with respect to the property. As a general rule, compensation with respect to the performance of services is taxable to the person who performed the services unless the compensation is assigned to and...
Why are optical isomers important to one & all for life? Please specific- not general. And please do not use google, because the google answer were incorrect.
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