Question

Constants1 Periodic Table Part A An 889-g copper ball is dropped from rest from from the top of platform 8.80 m above the ground. The collision between the ball and the ground is totalily ineliastic, Le, the ground and ball stick together If all the ball's kinetic energy goes into heating the ball (which it does not, but lef's just assume that it does by how much does the bair's tempereta change? Submi Request Anwr Provide Feedback Next )

Answer 1

Specific heat of copper c = 385 J/kg degree c = 0.385 J/g degree C mass of ball m = 88.9 g height h = 8.8 m kinetic energy of the ball just before collision} = Initial gravitational P.E of the ball = mgh we know heat absorbed by the ball Q = mc Delta T therefore mc Delta T = mgh (because from law of conservation of energy) Delta T = gh/c = (9.81 m/s^2) (8.8)/385 = 86.328/385 = 0.2242 degree c