Question

Calculate the solubility at 25 °C of Zn(OH), in pure water and in a 0.0130 M ZnSO, solution. You'll find K, data in the ALEKS Data tab. Round both of your answers to 2 significant digits. solubility in pure water: 19 X TO 02 solubility in 0.0130 M 2.50, solution: 0

Answer 1

Solubility of Zn(OH) in presence of water- Zine hydroxide [Zn(OH)₂ is a sparingly Soluble salt. It dissociates in water ver. weekly: The dissociatiation equilibrium in water can be written aso ICE table Zn(OH) Zn2+ (aq) + 2 OH-cas Initial : Solid solid +23 Equilibrium solid 25 where 'S' be the molan solubility of Zn(OH)2 in water. and concentration of solid not included Solubility product of In (OH)2 Ksp ²3.0x10 1.6 Ksp = [Zn2+] [OH-] O n tot Change: in water, ucz 310x101.6 = 5x as) 2) 3.0 x1616 » Si a 4.217x10-6 m mass of Zn(OH)₂ = 99.424 g/mol : solubility in water = 4.217x10-6 more a 1 L - 1 mal 4.1927 X10

solubility of Znot) in Zu say. Znottle if a sparingly soluble salt and solubility of Zn(OH)₂ decreases in presence common in En son dissociates as En sout Zn2+ + soy2- . [zu 2+] = 0.0130m NOW we consider the ICE table of Zn(OH)₂ 1(Etablet Zn6H)2 6. Initial: Change: solis Solid solid Zn2+ coas +20H-can 0.0130 +2s (0.0130+5) 25 &S Eauilibriums so, its i Zn (altlis sparingly soluble salt, dissociation can be considered as negligible. [7n2+] = 0.0130+5) = 0.0130 m 0.013 3) - 2 a kopa [2224] [OH-] 360x10-16 = ( 9630939 (25) 3.0x100 = (0.013 х4) 5 s. 75955 tiofm Molar mass of Zn(OH)2 = 99.424 g/mol i solubility in zn sou 7.5955x10 mo 99424 g - 7.5517 xió 67 g/L so, solubility dereases in presence 1 1 mole of common in