Ksp of BaCrO4 = 1.2*10^-10
BaCrO4(s) -----------------> Ba^2+ (aq) + CrO4^2- (aq)
------------------------------ S ------------- S
Ksp = [Ba^2+][CrO4^2-]
1.2*10^-10 = (S)(S)
1.2*10^-10 = (S)^2
S = 1.1*10^-5
molar solublity = 1.1*10^-5 mole/L
molar mass of BaCrO4 = 253.37g/mole
solubility of BaCrO4 in g/L = 1.1*10^-5 *253.37
= 2.8*10^-3g/L >>>>answer
Ksp of BaCrO4 = 1.2*10^-10
BaCl2(aq) --------------> Ba^2+ (aq) + 2Cl^- (aq)
0.01M 0.01M
BaCrO4(s) -----------------> Ba^2+ (aq) + CrO4^2- (aq)
------------------------------ S+0.01 ---- S
Ksp = [Ba^2+][CrO4^2-]
1.2*10^-10 = (S+0.01)(S)
1.2*10^-10 = (S+0.01)(S) [ S + 0.01 = 0.01, S<<<<<0.01]
1.2*10^-10 = 0.01*S
S = 1.2*10^-10/0.01
S = 1.2*10^-8
molar solublity = 1.2*10^-8 mole/L
molar mass of BaCrO4 = 253.37g/mole
solubility of BaCrO4 in g/L = 1.2*10^-8mole/L * 253.37g/mole
= 3.04*10^-6g/L >>>>answer
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