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What is the change in enthalpy for the reaction when 2.00 mol of iron(II)oxide, FeO, reacts...

What is the change in enthalpy for the reaction when 2.00 mol of iron(II)oxide, FeO, reacts to form Fe 3O 4( s)? 6FeO( s) + O2( g) 2Fe3O 4( s) ∆H rxn = - 635 kJ/mol rxn

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Answer #1

Equation 6FeO(s) O2(g -635 kJ/mol >2Fe304(s); AH -635 kJ Amount of heat released = 2.00 mol FeOx- 6 m ol FeO -211.7 kJ = -212

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