Which of the following electron configurations is not possible for an atom in an excited state? I know the answer is D but I do not understand how E is possible since 4s14 would mean 14 electrons in an s orbital. Doesn't that exceed the limit of 2???
A) |
1s22s22p63s23p63d104s14p1 |
D) |
1s22s22p63s23p63d104s2 |
B) |
1s22s22p63s13p5 |
E) |
1s22s22p63s23p63d104s14p3 |
C) |
1s22s22p63s23p23d2 |
A) 1s22s22p63s23p63d104s14p1
B) 1s22s22p63s13p5
C) 1s22s22p63s23p23d2
D) 1s22s22p63s23p63d104s2
E) 1s22s22p63s23p63d104s14p3
Answer : D)
Explanation :
in option D , there is no possibility of exited state electron configuration. because there all are completely filled.
in option E , 4s14p3 , so here one electron from s orbital jumped to p orbital. so this is exited state configuration.
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