Question

An object of mass 2.5 kg has a momentum < 7, 7, 1 > kg m/s At this instant the object is acted on a by a force < 25, 50, 100 > N for 3 x 10-3s What is the momentum of the object at the end of this time interval? < 6.92, 6.85, 0.70 > kg m/s <0.07, 0.15, 0.30> kg m/s < 7.04, 7.08, 1.15 > kg m/s < 7.08, 7.15, 1.30 > kg m/s None of the above

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Answer #1

Given Force ,Fin (25i + 50j + 100k)N

time,t3 10-3s

initial momentum,mv_{i}=(7hat{i}+7hat{j}+1hat{k})kgm/s

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Use Formula F_{av}*Delta t=mDelta v

F_{av}*Delta t=m(v_{f}-v_{i})

F_{av}*Delta t=mv_{f}-mv_{i}

F_{av}*Delta t+mv_{i}=mv_{f}

mv_{f}=(25hat{i}+50hat{j}+100hat{k})N*3*10^{-3}s+(7hat{i}+7hat{j}+1hat{k})kgm/s

mv_{f}=(25hat{i}+50hat{j}+100hat{k})*3*10^{-3}+(7hat{i}+7hat{j}+1hat{k})

mv_{f}=(0.075hat{i}+0.15hat{j}+0.3hat{k})+(7hat{i}+7hat{j}+1hat{k})

mvf- (7.075i + 7.15j + 1.3k)

mvf (7.08i+7.15j +1.30k)kgm/s

ANSWER: Option 4

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