2. Describe how you would prepare 250.00 mL of 0.150 M ammonium ion solution beginning with...

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Answer 1

Answer #1

we know that

molarity = [( weight /gram molecular weight ) X 1000] / volume

weight = (molarity X volume X gram molecular weight ) /1000

given data in the problem

volume = 250ml

gram molecular weight of (NH₄)₃PO₄ is 149.09 g/mol

molarity = 0.150 M

weight = (0.150 X 250 X 149.09) /1000

required weight = 5.5908 grams

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Answer 2

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