how many milliliters of a stock solution of 2.00 M KNO3 would you need to prepare 100.0 mL of 0.150 M KNO3
how many milliliters of a 0.25 M HCl solution would be used to prepare 100.0 mL of a 0.050 M solution of the acid?
A) How many milliliters of a stock solution of 7.00 M HNO3 would you have to use to prepare 0.150 L of 0.530 MHNO3? B) If you dilute 11.0 mL of the stock solution to a final volume of 0.340 L, what will be the concentration of the diluted solution?
(a) How many milliliters of a stock solution of 11.0 M HNO, would you have to use to prepare 500 mL of 0.200 M HNO,? ml (b) If you dilute 21.0 mL of the stock solution from part a) to a final volume of 3.00 L, what will be the concentration of the diluted solution? (Watch the 7. -13 points My (a) How many milliliters of a stock solution of 12.0 M HNO, would you have to use to prepare...
How many milliliters are required to prepare 100.0 mL of a solution that has 5.0 mg Cu/mL from a solution of Cu(NO3)2 0.80 M? The answer is 9.8 mL, can someone please explain how to get this result?
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (pK. = 4.20) and 0.220 M sodium benzoate. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid: mL sodium benzoate: ml
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (pK; = 4.20) and 0.240 M sodium benzoate. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid: ] mL sodium benzoate:
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.180 M sodium benzoate. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid: mL mL sodium benzoate: sodium benzoate: ml.
A. How many milliliters of a stock solution of 5.60 M HNO3 would you have to use to prepare 0.180 L of 0.530 M HNO3? B. If you dilute 20.0 mL of the stock solution to a final volume of 0.350 L , what will be the concentration of the diluted solution?
PART A How many milliliters of a stock solution of 7.00 M HNO3 would you have to use to prepare 0.200 L of 0.490 M HNO3? PART B If you dilute 17.0 mL of the stock solution to a final volume of 0.280 L , what will be the concentration of the diluted solution?
How many milliliters of 0.150 M FeCl, solution are needed to react completely with 20.0 mL of 0.0450 M AgNO3 solution? How many grams of AgCl will be formed? The net ionic equation for the reaction is Aga4 + Cl24) AgCl)