6.
a)
Moles of HNO3
= M1V1 = M2V2
Or , M1 × 11.0 = 0.200 × 500
Or, M1 = 9.09 mL.
9.09 mL of stock solution is needed.
b)
Final volume (V2) = 3.00 L = 3.00×1000 mL
Now,
M1V1 = M2V2
Or, 11.0× 21 = M2 × (3.00 × 1000)
Or , M2 = (11.0×21/3000) = 0.077 M.
Concentration of dilute solution = 0.077 M.
7
M1V1= M2V2
Or, 12 × V1 = 0.200 × 0.500 L
Or, V1 = (0.200×0.500/12)
Or, V1 = 0.0083 L = 0.0083×1000 mL = 8.33 mL.
Volume of stock solution needed = 8.33 mL.
b)
Final volume (V2) = 4.00×1000 = 4000 mL
Now,
M1V1= M2V2
Or, 12 × 30 = M2 × (4.00 ×1000)
Or , M2 = (12×30/4000) = 0.09 M.
Concentration of dilute solution = 0.09 M
(a) How many milliliters of a stock solution of 11.0 M HNO, would you have to...
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