A. How many milliliters of a stock solution of 5.60 M HNO3 would you have to use to prepare 0.180 L of 0.530 M HNO3?
B. If you dilute 20.0 mL of the stock solution to a final volume of 0.350 L , what will be the concentration of the diluted solution?
1 ) According to Dilution law,
M 1 V1 = M2 V2
Here. M1 = 5.60 M. M2 = 0.53 M
V1 = ? V2 = 0.180 Lit =( 0.180 x 1000) ml
5.60 M x V1 = 0.53 M x (0.180 x 1000) ml
V1 = 0.53 M x 180 ml / 5.60 M
V1 = 17.036 ml HNO3
2 ) Molarity of Stock solution ( M1) = 5.6 M
V1 = 20 ml
M2 = ?
V2 = 0.35 Lit =( 0.35 x 1000) ml
V2 = 350 ml
From Dilution law, M1 V1 = M2 V2
M2 = M1 V1 / V2
M2 = 5.6 M x 20 ml / 350 ml
M2 = 0.32 M HNO3
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