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How many milliliters of a stock solution of 8.50 M MgCl2 would you have to use...

How many milliliters of a stock solution of 8.50 M MgCl2 would you have to use to prepare 650.0mL of a 1.60 M MgCl2 solution?

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Answer #1

We will use the formula

M1V1 = M2V2

8.5 x V1 = 1.60 x 0.650

V1 = 0.122 L or 122.35 mL of stock solution we would require in this case

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Answer #2

yolume 2. Nooheuivalents sho ald be Some no moles) 1.5) (v) 1.6)(650) 9.5 22.35 mAngwey

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