Question

How many milliliters of 0.150 M FeCl, solution are needed to react completely with 20.0 mL of 0.0450 M AgNO3 solution? How many grams of AgCl will be formed? The net ionic equation for the reaction is Aga4 + Cl24) AgCl)

Answer 1

11 Ag++ (0-y Age - No of malen; Melanity x Volume 2 Z 1000 ou No of moles of AgNO3 = 0.0450 mol x 2000 L = 0.0009 mol 1 mole AgNO3 breaks to give 1 moke Agt and 1 mole Noz: & No of males of Ag t = 0.0009 mal Also, 1 male FeCl₂ breaks to give 1 mole Fe3+ and a - 3 molas (é ions. - According to son , Ag+ and cr reacts in 1:1 ratio s oo No of moles of Felly required= No of moles Agt i _ = 0.0009 mal = 0.0003 mala 3 .- Veing & Volume of Felly = 0.0003 mol = 0.002 L - 0.150 mollt = 2 mL (Using (3) No of moles of All formed = No of moles of Ag+ reacted __= 0.0009 mal 0 Mass of AgCl formed= No. of moles x Molar Mass = 0.00 09mel x 143.32 g mol = 0.129 g.