Question

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide.
4HCl(aq)+MnO2(s)⟶MnCl2(aq)+2H2O(l)+Cl2(g)
A sample of 34.5 g MnO2 is added to a solution containing 43.1 g HCl.
What is the limiting reactant?
What is the theoretical yield of Cl2? theoretical yield: g Cl2
If the yield of the reaction is 73.9%, what is the actual yield of chlorine? actual yield: g Cl2

Answer 1

Mno, ano2 0 = .40 moe NO. OF Moles Of MNOZ MOLES OF Mno. a mass of MW of 34.59 86.94 gmaet No. of moles of Hel = 43.19 1018 moe S 36.458 gmoet ACCORDING TO BALANCED EQUATION, 1 mol MnO2 NEEDS 4 mol Hel. so O. 40 mol rano, NEEDS I 0-40 mol x 4 = 1.60 mol Hel BUT only 10 18 mol Hel IS PRESENT. . So Hel is limiting REAGENT. 4 mol Hill PRODUCES A moe che so 118 moe Hee PRODUCES = 1.18 x L - 0.295 mu Uy. THEORETICAL YIELD = #mol C₂ x 9w of ų = 0,295 mol x to 9 9 = /20.92 g PERLENT 416o - Actual uico X 100 HEORETICAL YIED ACTUAL YIELD x 100 73.8 = 20082 g - Actually yielo of cly = 15.469 |