Question

iF 16.2 g of HNO2 is placed in 0.8L of water calculate the Molarity of the solution and Identify the Solute and the solvent: comment on the strength of the electrolyte in this soln & why

M=0.43 solute is HNO2 and Solvent is water

Answer 1

Answer: When a substance is dissolved in water, water acts as the solvent and the substance that is added in water is the solute.

So, the solute is HNO₂and the solvent is water.

HNO₂ is a weak acid. So, it does not completely dissociates in water. Hence, the elctrolyte, HNO₂ in this solution will behave as a weak electrolyte.

Molarity is greien as: nolarity (M) = moles of solute Volume solvent int noles noles of HNO2 = of ANO mass of HNO. - Molar mass of HNO, IC molar mass of ( HNO₃ = 470gnet? 16.29 47.0gmel 470) Now, no Now, notarity (M) = (16-2/4710) not mol - 0.8L 16.2 [mol/= M ( 162 ) moll = 0.4308 moth ñ 0.43 mol/l = 0.43 m) molanty (m) of this solution is 0.43 m Hence, the