Question

2. Hummingbird wings can be modeled as simple harmonic oscillators. The displacement of the wing tip is +35 mm and the duration of a single cycle is 40 ms. 

A. Sketch the position versus time graph for the wing tip for 3 complete oscillations. 

B. What is the frequency of the oscillations? 

C. What is the maximum speed of the wing tip? 

D. What is the maximum acceleration of the wing tip in m/s and in units of g?

Answer 1

Answer 2

a positim vs time ta sons 120ms As the is It is simple has monic motim, so displacement | pocisim vs tim graph einusodal 16 sime period of oscillation Те ч0 м с Frequency na t= tuaios 10 = 25Hz amplitud (a)= € 35mm angular speed (w) - 2017 - 2018 10 8 sot sad se Vmane wa – 504 4354 10 3 = 5.5msee d Maam accelerarm . omax. 2 о = (504) 2&35 3 – 863.59 m/se2 - 863.6 m2 = 88.039 mi sen

Answer 3

Amplitude A = taslm t35 Mm Time poiid T 4oms=40x t6Sec ASimwt V=d Aw coswt ap= 3SAM -35MM oquene = 25 HZ 40x.163 VMAK=Aw 4 A( 35K162 K3-1 7 40XI03 5-49 MIS 2 Awt- 2 X3-11 YOXIO 35XO024GX10 8627 x (o3 Oran