Question

Review I Constants Suppose you take and hold a deep breath on a chilly day inhaling 1.7 L of air at 0° C. Assume that air pressure is 1.0 atm

Answer 1

By ideal gas equation,

P*V = n*R*T

So, moles of gas(n) = P*V/(R*T)

given, P = 1 atm

V = 1.7 L

T = 0 deg C = 273 K

R = 0.0821

So, n = 1*1.7/(0.0821*273)

n = 0.076

Since, heat transfer(Q) = n*C*dT

given,

C = 29.1 J/(K*mole)

dT = 37 - 0 = 37

So,  Q = 0.076*29.1*37

Q = 82 J

Part B.

Since pressure is constant,

So, by ideal gas equation,

Vi/Vf = Ti/Tf

here initially,

Ti = 273 K   &    Vi = 1.7 L

Tf = 273+37 = 310 K

Vf = ??

So,

Vf = (1.7*310)/273

Vf = 1.9 L

Change in Volume = Vf - Vi = 1.9 - 1.7 = 0.2 L

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