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The pOH of an aqueous solution at 25°C was found to be 8.80. The pH of this solution is The hydronium ion concentration is M.

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Answer #1

pH + pOH = 14

pH = - log [H+]

H+ can also be written as H3O+ in aqueous solution

pOH = -log[OH-]

ponof aq. Sot – 8.80 pH + poH = 14 pH + 8.80 = 14 pH = 5.2 PH = -log [he] - log [H] = 5.2 [41] = 10 512 = 6.31x10-6 por=- le

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