An ammeter with a scale ranging from 0 to 15mA has a resistance of 5Omega. How should the instrument be connected together with a resistor (and with what resistance) to measure: (a) a current from 0 to 0.15A, (b) a potential difference from 0 to 150V
(a)
put a small resistor in parallel with the meter to measure 150
ma (0.15A).
total R will be 0.5 ohms, but you need the added resistor a little
larger so the total will be 0.5.
R = 0.5*5/(5-0.5) = 0.555 ohms
(b)
R = E/ I = 150V / 0.015A = 10000 ohms
Internal Resistance is 5 ohms
10000 - 5 = 9995 ohms is the required resistance in series with the meter.
An ammeter with a scale ranging from 0 to 15mA has a resistance of 5Omega. How...
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