let in compound number of moles of C and H be x and y respectively
Number of moles of CO2 = mass of CO2 / molar mass CO2
= 2.56/44
= 5.818*10^-2
Number of moles of H2O = mass of H2O / molar mass H2O
= 0.786/18
= 4.367*10^-2
Since 1 mol of CO2 has 1 mol of C
Number of moles of C in CO2= 5.818*10^-2
so, x = 5.818*10^-2
Since 1 mol of H2O has 2 mol of H
Number of moles of H = 2*4.367*10^-2 = 8.733*10^-2
Divide by smallest:
C: 5.818*10^-2/5.818*10^-2 = 1
H: 8.733*10^-2/5.818*10^-2 = 1.5
Multiply by 2 to get simplest whole number ratio:
C: 1*2 = 2
H: 1.5*2 = 3
So empirical formula is:C2H3
Answer: C2H3
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