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A survey was conducted that asked 1086 people how many books they had read its past year Resh idcated that-15 9 books and s. 17 4 books Canaud a ses read Imerpret the interval Construct a98% confidence interval for the mean number of books people read and innerpret the resia select the correct choice below and nne answer bom te cumpite yoshke Use ascending order. Round to two decimal places as needed) OA. Then is a 98% dance that the truo mean number of books read is between []and B. There is 98% confidence that the population mean number of books read is between O c-H repeated samples are taken, 98% of them wil have a sample mean between and and
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Answer #1

The provided sample mean is X 15.9 and the sample standard deviation is s- 17.4. The size of the sample is n-1086 and the required confidence level is 98%. The number of degrees of freedom are df level is α : 0.02. 1086-1-1085, and the significance Based on the provided information, the critical t-value for a degrees of freedom is te 2.33. 0.02 and df 1085 The 98% confidence for the population mean μ is computed using the following expressionTherefore, based on the information provided, the 98 % confidence for the population mean u is V1086 15.9+ 2.33 x 17.4 -(15.9 - 1.202, 15.91.202) 2.33 17.4 CI 15.9 1086

CI = ( 14.70 , 17.10 )

Option "B" is correct.

There is 98% confidence that the population mean number of books reasons between 14.70 and 17.10

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