Solution :
Given that,
Point estimate = sample mean = = 14. 9
sample standard deviation = s = 16.6
sample size = n = 1004
Degrees of freedom = df = n - 1 = 1004 - 1 = 1003
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,1003 = 1.962
Margin of error = E = t/2,df * (s /n)
= 1.962 * (16.6 / 1004)
= 1.028
The 95% confidence interval estimate of the population mean is,
- E < < + E
14.9 -1.028 < < 14.9 + 1.028
13.872 < < 15.928
(13.87 , 15.93)
Option B is correct
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