Question

Write a psudocode:

1. Define a function called authorize that takes in 2 strings, uName, and passwd, as arguments and produces a Boolean as output. Your function should output True if both the username is “batman” and the password is “rulz” and false in any other situation. (KEEP IN MIND: this function didn’t say anything about looping. It performs authentication on only 1 pass)

Answer 1

Pseudo code:

def authorize(uName,passwd) //define the function

{

if(uName=='batman' and passwd=='rulz') return true; //check the condition

else return false;

}

print(authorize('batman','rulz')) //check the output by printing

Python code:

def authorize(uName,passwd):
if(uName=='batman' and passwd=='rulz'):
return True
else:
return False

user_name = input() #username
pass_word = input() #password

print(authorize(user_name,pass_word))

C code:

#include <stdio.h>
#include<string.h>
#include<stdbool.h>

int authorize(char *uName,char *passwd)
{
if(strcmp(uName,"batman")==0 && strcmp(passwd,"rulz")==0) return 1;
else return 0;
}

int main()
{
int a = authorize("batman","rulz1");
if(a==1) printf("True");
else printf("False");
return 0;
}

I have given the pseudo-code and python code, C code for your reference. As you did not mention a particular language, I have given python and C code. The pseudo-code is the same for any programming language. There is no use of a loop for the validation here, only an if-else statement is required. I hope you find this helpful.