Question

2 pts Question 2 Calculate the cell potential for the galvanic cell (in volts) in which the following reaction occurs at 25.0°C, given than [Ti2] = 1.7 M and [Au3]-0.463 M. Standard reduction potentials can be found here . 3TY + 2Au) 3Tie)+2Au Note: Pay attention to the number of electrons transferred. Do not include units in your final answer Report your answer to two places after the decimal.

Answer 1

​​​​​​Anodic reaction: 3 Ti(s)-------> 3Ti²⁺ + 6e^-

Given Electrochemical reachosts 3 Ti(s) + 2 Ay 3tlah) - 3 T. 21 (ap) +244 (S) Cell representation is TilTi 2+ ( al, 1.7M) || Ayst / Ay Co 461M) anode Cathde 21 T - - 1.630v 1.50V A B/A - Eande - - 1.50 (-1.630) = 1.5+ 1.63 Calde Cell - 3.134 Nernist equchon is a E = Ecall - in E log Preactants] - Eo - 0.089 log e Product] = 3.13 1 – 0.059 log (1.17) (0-463 77 = 3.134 - log22.92)xo.org - 769 N 24.8.13-0.134. = 8.13 0.225 - 3.10v.

Cathodic reaction: 2 Au^{​​​​​3+}+ 6e^- -------> 2 Au (s)

Therefore number of electrons transferred= 6

Variation of electrode potential with concentration of electrolyte is given by Nernst equation.