Question

can you show me the IUPAC NAMES

- Lower Z configuration Higher ranked substituents (Cl and Br) are on same side of double bond Lower - H B r Higher E configuration Higher ranked substituents (Cl and Br) are on opposite sides of double bond Problem 7.7 Determine the configuration of each of the following as Zor E as appropriate: Y OH Sample Solution (a) One of the doubly bonded carbons bears a methyl group and a Page 251 hydrogen. According to the Cahn-Ingold-Prelog séquence rules, methyl outranks hydrogen. The other carbon atom of the double bond bears a methyl and a CH, OH group. The CH, OH group is of higher priority than methyl. Higher (C) HECCH OH Higher COHH снин)

Answer 1

Hint if if & check heavier group - two heavier group sameside => [zJ two heavier group different side a LE) hearior (a) t ow => [13) 123-2-m Zj-2-methyl but-2-en-101 |LZ)-3-(2-fluoroethyl) hept-zene (b C res Br => [125 12)-3-42-fluoroethyl) horizon. ow =LED 71€ 3-3-tot-buty)pent s en- E1-3-(tert-buty Upent-3-en-1-01 VOH => El-pent-2-en-3-g/ cyclopropane