3. Life Satisfaction scores for several individuals are shown below. Test whether these scores come from...
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3. Life Satisfaction scores for several individuals are shown below. Test whether these scores come from a population with a mean of 50. You may assume that these scores come from a normally distributed population. 67 58 59 75 74 74 67
A research study concluded that self-employed individuals do not experience higher job satisfaction than individuals who are not self-employed. In this study, job satisfaction is measured using 18 items, each of which is rated using a Likert-type scale with 1–5 response options ranging from strong agreement to strong disagreement. A higher score on this scale indicates a higher degree of job satisfaction. The sum of the ratings for the 18 items, ranging from 18–90, is used as the measure of...
While the following simple random samples of Statistics test scores both come from populations that are normally distributed, we do not know the standard deviation of the populations. The first simple random sample is drawn from the scores on Exam 1 for an on-line Statistics class and the second simple random sample is drawn from the scores on the exact same Exam 1 for an on-land (traditional) Statistics class. Using the null hypothesis that there is no difference in the...
A principal claims the students in his school have above-average test scores for a particular standardized test. A sample of 50 students from his school were found to have an average test score of 77.2. The population mean for test scores for this particular test is 75, with a standard deviation of 9 (so we can assume that the population test score is normally distributed). Set up a hypothesis test to determine whether this principal’s claim is correct (use alpha...
Question 1 (30 marks) The scores of 60 students in a test are: 58 49 48 62 50 76 61 82 60 72 70 35 61 55 82 66 50 47 36 58 84 55 68 32 62 58 48 75 80 49 55 67 71 46 40 57 69 70 52 60 48 53 42 68 54 60 63 70 72 68 42 55 36 70 36 82 66 46 59 50 (i) Find the mean score of the...
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10. To test whether a college course is working a pre- and post-test is arranged for the students. The results are given below. Compare the scores with a t-test as indicated. Use α 0.05 to test the claim. Use the 5-step method. a) Assuming the scores are randomly selected from the two groups. Assume equal variances. b) Assume that the scores are pairs of scores for ten students Test...
The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 1427 1225 989 700 720 839 729 740 542 620 1442 946 (a) Find the sample mean. x=
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VI/ Test scores from a math midterm are as follows: 79, 90, 85, 89, 70, 59, 75, 64, 83, 78, 75, 77, 78, 77, 67, 85, 74, 52, 87, 72, 69, 76, 61, 77, 93, 86, 79, 90, 74, 67, 51, 75, 77, 82, 78, 60, 86, 72, 91, 95, 82 Complete the frequency distribution table to include all data a. Class Tallies Class Midpoint Relative Cumulative Frequency relative freq boundaries Frequency 51 57...
The frequency distribution shows the results of 200 test scores Are the test scores nomally distributed? Use α-0.10 Complete parts is) through (e) Class boundaries Frequency, 49.5-585 2D 58.5-67.5 51 67.5-76.5 B0 76.5-85.5 35 95.5-94.5 Using a chi-square goodness-of-fit test, you can decide, with some degree of certainty whether a variable is normally distributed. In all chi-square tests for nomality the null and alternative hypotheses are as follows Ho The test scores have a nomal distribution Ha The test scores...
The scores on a test from an entire class (ie. entire population) are listed below. Find the mean and standard deviation of the scores. Then determine what percent of the data is within 1 standard deviation of the mean. 71 72 71 82 79 65 77 71 73 78 75 The mean is 74 (Simplify your answer) The standard deviation is 4.6 (Simplify your answer. Round to the nearest tenth) % of the data is within 1 standard deviation of...