Question

RCES Chapter 27, Problem 073 Wires A and B, having equal lengths of 41.1 m and equal diameters of 2.80 mm, are connected in series. A potential difference of 60.8 V is applied between the ends of the composite wire. The resistances are RA = 0.113 2 and Rg = 0.646 2. For wire A, what are (a) magnitude of the current density and (b) potential difference V? (c) Of what type material is wire A made (see the table below)? For wire B, what are (d) ) and (e) V? (f) of what type material is B made? IlII Resistivities of Some Materials at Room Temperature (20°C) Material Resistivity.p ( m) Temperature Coefficient of Resistivity, a (K ) Eudy Silver Copper Gold Aluminum Manganin Tungsten Iron Platinum Typical Metals 1.62 x 10-5 1.69 X 10-8 2.35 X 10" 2.75 X 10-1 4.82 x 10- 5.25 X 10- 9.68 x 10- 10.6 x 10 Typical Semiconductors 2.5 x 10 8.7 x 10-4 28 x 10- Typical Insulators 10 -10 -101 41 X 10- 43 x 10- 40 X 10- 4.4 x 10-> 0.002 x 10 45 x 10- 65 x 10- 39 x 10- -70 x 10-> Silicon, pure Silicon, n-type Silicon.p-type Glass Fused quartz "An alloy specifically designed to have a small value of a "Pure silicon doped with phosphorus impurities to a charpe Carrer density of 10 Pure silicon doped with aluminum impurities to a charge carrier density of 10 (a) JA = Number Units Units (b) VA = Number (c) (d) JB = Number (e) V8 = Number Units Units (f) Click if you would like to Show Work for this question: Open Show Work

Answer 1

0.7SG 6.188 x 10-6 Area A Tor _ * ( 2.80 16 m _ 6.188 x16 ben Equivalent resistance Reg-RA+RB 0.259 s cas JA- 7 / where I = 60.8 - 80.11 A Jn 80 /130x107 Alma) (3) VA = I RA= ( 30.11) Co.113) = 19.05 ) @ Resistiwa p- RA - (0.113)(6.188 xl.-9) = 1.69810 8. un ... The materialis / Coppen) d JB = 1 = 601 - 11.30 x16? A leme ] (es VB= I RR= (1, 2g x lot 8o. 1) Co. 646) - 151.75 v1 (f) (0.646) (6.158810-4) - - 9.68710-8 41.1 80 41 The material is Iron

Kindly upvote:)