Q 11 ) Here null hypothesis Ho : = 4.73
Ha : 4.73
n = 43 , x bar = 5.52 , s = 3.64
d.f = n -1 = 42
test statistic
t = xbar - / (s/n)
t = (5.52 - 4.73)/(3.64/43)
t = 1.42
p -value = 2* P( t > 1.42) d.f = 42
p-value = 0.1630
Q - 16)
Given Ho : = 14
H1 : > 14
n = 41 , xbar = 15.4 , s = 5.8
test statistic t = (15.4 -14 )/ (5.8/41)
t = 1.55
p-value = P( t > 1.55 ) d.f = 40
p -value = 0.0645
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