Question

After running the experiment, a student found that the unknown sample is 5.30 x 10-6 M in Red 3 dye. How many milligrams of Red 3 dye should this student use to make 5.00 Liters of the unknown sample? (Check the lab handout for the molar mass of the Red 3 dye if needed) 4.66 mg 0.0465 mg 8.40 mg 0.00233 mg 23.3 mg

Answer 1

Hi,

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Given that, Molarity of the solution,

M = 5.30 x 10-6 M

Volume,

19= A

Therefore, No.of moles of Red 3 dye in the solution is given by,

n = molairty x V = 5.30 x 10-6 M X 5 L

in = 2.65 x 10-5 mol

We have, Molar mass of Red 3 dye, M=879.86 g/mol

Therefore, mass of Red 3 dye in the solution is given by,

m = n x M = 2.65 x 10-5 mol x 879.86 g/mol

..m = 0.0233 g

We know that, 1 g = 1000 mg

::m = 0.0233 x 1000 mg

:: m = 23.3 mg

So the correct option is OPTION (5) 23.3 mg

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