Question

Calculate the volume in milliliters of a .35 mol/L iron(III) bromide solution that contains 75 mmol of iron(III) bromide . Round your answer to 2 significant digits.

Answer 1

Anower Moler of Solute = Molurity of solufe x Volume of solution moles of FeBrgé = Molarity of Fe Brzx Volume of solution 75mmol = 0.35 mol x Volume of solution volume of solution = 75m mol 0.35 moll - 75 X 103 mo) 0.35 mol/L = 214.29 x{10-32) = 214.29 m2 rounding off to a significant Volume of solution = 210 mL digits | 210 ml) 210mL