Calculate the volume in milliliters of a 1.33/molL iron(III) bromide solution that contains 150.g of iron(III) bromide FeBr3. Round your answer to 3significant digits.
Sol . As molarity of solution = 1.33 M
Mass of FeBr3 = 150 g
Molar mass of FeBr3 = 295.557 g /mol
So , Molarity of solution = (Mass of FeBr3/Molar mass of FeBr3 ) ÷ Volume of solution
So , volume of solution = (150/295.557) ÷ 1.33 = 0.3816 L
Therefore , volume of solution = 0.3816 L = 382 mL
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