Question

A chemist prepares a solution of iron(III) bromide FeBr3 by measuring out 57.3g of iron(III) bromide into a 50.mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's iron(III) bromide solution. Be sure your answer has the correct number of significant digits.

Answer 1

mass of Iron till) bromide =57039 (Fe Brg) Molar mass of fe Bory = 56+3x80 = 56+240 = 290g/mole. no. of moles of Fe Brz = given mass of fe Brz Molar mass of fe Bry 2 57.3 296 mole 2 MIESTE 0.194 mole Molanty û defined on the no. of moles of bilute present in ll of solution, MreBrya no. of moles of fe Bry 0.194 Volence of solution (inds mole 50 e 1000 More Bry? 3.80 M (Concentration of fabry in molele)