Notes:
- Dear Students! The above is a very tedious solution. Please
take your time with the solution and I am sure you will understand
it well
- I have solved all the four parts in elaborate steps, mentioning
them in order. Follow the steps and you will get it in a gist.
- A lot of data has to be assumed in this solution and a lot of
standard tables have used. I have mentioned all the tables used
everywhere I took some standard value. You can find them in your
machine design textbooks. I will also give reference to the books I
used.
- Please rate my work and leave a comment for me!
- At last, feel free to discuss anything about the solution in
the comment section.
References:
Design of Machine Elements By V. B. Bhandari, TMH Publications,
ISBN 0070681791, 9780070681798.
Machine Design, By R. S. Khurmi.
All the best!
assembly Giveno A Mecipuo cating compressore- motor - connected by a v-Belt design o solution here we will be using a esta of standard Charte tables and graphs far v-Belt. f will mention the so name of each graph ( table but will not attach them. wat students are advised to look up sare them fram net. However of will mentics all the values used, system Analysis t assumptions . Nm = 1800 RPM P = 7-4 RW lio INOM CON PRESOR 450-3 Asumptions : O team standard compressor sizes a speeds ull will assure speed of camp = MC = on rpm. Nowhere will service fee if hip [day 3 space Quailable = im. ☺ angle of Geloove = 6 Belts are made of leather ① Tweekness of belt - 5mm © Marm strese in belt = 2-25 Wimme site to
WAS Amputatióne fou a reasonable u Belt drive. Step! conreuth focar according Team table of corection we get fa = 1.3 for driving to rewill .(Fa). factor do sewey" a compressor of 7.5kw. W Step 11 Design Power, Design Power = fax pouve Transmitted = 103 x 67-460 kW) r Q.7 kW. RALARIA Step 111 Pitch diameter of smaller a begque pulleys. from the table of a selection of cross-section of V-Belt' and 6 anerscore of etendere coss-sectiona the minimum pitch diameter fele small pulley = 200 mm Speed ratio = 1800 - 30 Lobo d = 200mm d.o=3-00 (200) = Whatrin 600 mm hote: I can he meassweed from the table - 6 pusfired pitch Diameter of Pulleys that diameters have preferred values. both seep iv Pitch hength of Belt. fulam & selection of cross-section of u-Belta table we have established that we will be wring a veess belt drive. Pean the geometrical relations of a class V Belt we have i n
2 40 wength of eet L = 22 + 2CD+B) + Combe-o (= 2(1000) + mi correo +200) + cena 200) 2 2 421000) 12-56 40 bu het oolours LF Boboteabebunn. 3296 mm. Step i preferred Petch hength. from the table G Nominal pitch length of standard sizes of v-Belt" ull have its assumed to have pitch length of 3600 mm 3200mm Seprio coment centru distancu. substituting this value of bitch length oo mm) qet = 1017 07 mm 32000 in ☺ , ull Fig 1; Georetrúc Representath of close V-Belt
26 Step ulli conecta factor for are of contact fal heen fig liwe hou As = 180-2 üst ( Dod) 1$ = 148.62" fuam tabeu o corrent factor for are length i fa l 0.92 Step ull: power rating of engll v-Belt team table Power Rating in kW fox B-section, V-Beeted p= 6.36 kW Seep in Number of pets: - Design Power Number of betle al quies by i (Pawess Rat)x( fe )x fu Neembar of belte = a.7 kW = lol (7-5)x (1-3)*(0.92) so we will use 2 belts. (6) 2014 00:05: weest belt velvity = v= idn t (200) (1800) Gocrooo 60 C1000) V=1&.84 ms 88 = 148.62 0 ~ 2558 1 rad The density of leather = 0.959/ cc,
volume of im helt in ce=lxbxh = 6oo) (6) (5) to m= 6.95) (100) (3/10) (5/10) ,b=width in mm m=(uits x 10 =3) b kg/m Now mue = (4.78X20-3) bx112-84)2 ran2 = 1.685 b from helt tension calcuations ull have 1 Pirmu ² zefa Pz-mve => Arrigesh 2013 (2:58) - 217. Poz-1•6856 s Pic 2.17 P2 - 1.9+16 - ☺. new meam steese in helt=2-25 N/mm? 65 maam tension - area of choss-seet A Pa = 6A = (2-25)*(56) 514.256 N Also from power ego of belts we know PK-P2=1000 (RU) - 1000 (7-4). 1884 Pi-P2 = 392.17 No- soluing 6). © + use Pi = 256.84 N P2 = 464.18 N b= 76.16 mm. t6 mm
SUR Sharinh a © Beaving selection fare conkrusson applications, bearings are subjected to high axial wad, a radial loads. Praefare axial I radial diffectiore of beavinge must be kept to visinum. Therefore we choose, Rolling tot Bearings Now the naam Radial wad ware le tensions compressor states the duim shaft at 600rpm са екресtеd a glu) 0 (0, 05 4 . het the mis acceptable diameter of shaft =40mm Bearing selectean es cas followx! fr= I ŁN, Lon = 10,000 hours , N=courpm ; d = homma Stepi Dynamic load capauty. The bearing is subjected to pure radial load Casswned) -> p=fr = 1 km New from bearing calculations we have life is leeu = Lò = con Lion - (Go) (600) C10,000) Lo = 360 million revi' fuam bearing loud life relationship, (= P(LO) Il . c= dgnanie load (N) ,P= 3(ball bearings 106 106 6
Capllio" = 3000 (360)"S ( 21,342.35 N. N 21.34 kn. Stebol! Selection of hearing team the standard table 6 Dimensions and seatic & Dynanie load capacities of single Уфа Коор 200m Bau ogying ш қощ here sia bearings we available for d=40mm, out of which hearing no 6208 (6=30700N) 's most suitable, Design of awe storage tank for mann cür presswel of 16 bar d im dranater now, since material of cylinder eu nest quien, let us take it to be made up of fair cubes free 10C4 Cout = 340 N/mm2 and H= 0.27). Also let us take factor of safety =5. Nowo, Di = 1000 MM , PO = 1.6 MPa , But = 340 N Imm? ; (fs) - 5 and 4= 0.27 (poisson's paleo) Step! The selection of cylindrical ea? tank is made up of dechill
R PAROLL material and ends are closed. Therefore C asio 024 ° и 4Ыf оно . OMAN MULLLLL seep 11 Feam Thickness of prinder clavarino's & Brine can we have 5= Sut = W errat Tensile serveryth - faltar of safety 6= 340 = 68 N/moo? clavarino's son Using to Di J5+ (1-24) p2 - 1 5= Design setess 4 = Poisson's Patio pe = ontoeral pressure s | 68 +(1-260-27) 1-6-11 L68 - (1-0.24) 1-6 t = 7:072 mm Thiedeness of gender required is 71 mm.