Question

NT RESOURCESChapter 17, Pro Chapter 17, Problem 65 Chalkboard Video Copy of Chapter 17 Problems, Sections 17.1-17.3 A sound wave with a frequency of 13.0 kHz emerges through a circular opening that has a diameter of 0.199 m. Find the diffraction angle θ when the sound travels (a) in air and (b) in water. (Note: The speed of sound in air is 343 m/s and the speed of sound in water is 1482 m/s) Units Chapter 17. Problem 17(a) Number hapter 17, Proble (b) Number Units Review Score Click if you would like to Show Work for this question: Qpen Show Work

Answer 1

Frequency (v) = 13 KHZ = 13 times 10^3 HZ diameter (d) = 0.199 m Diffraction angle: theta = sin^-1 (lambda/d) theta = sin^-1 (v/v_d) speed of sound in air (v_air) = 343 m/s theta_air = sin^-1 (343/13 times 10^3 times 0.199) = sin^-1 (0.1325) = 7.61 degree speed of sound in water (v_water) = 1482 m/s theta_water = sin^-1 (1482/13 times 10^3 times 0.199) = sin^-1 (0.5728) = 34.95 degree.