Question

Problem 12.46 - Enhanced - with Feedback Suppose one of the Global Positioning System s has a speed of 4.54 km/sat perige and a speed of 330 km/s apogee You may want to review (Pages 402 407) - Part A the distance from the center of the Earth to the satellite at perige is 2.24x10° kan what is the coresponding distance at apogee? IVO AXO 7.- 4.24. 109 Submit Previous Answers Request Answer X Incorrect; Try Again: one attempt remaining

Answer 1

Then, Sol" :- Given Leto Mars of Satellite om speed at perigee, V=4.54 kmis speed at abogee. Vo = 3.30 kms Distance from earth's center to the perigee 8p= 2.24 x109 km Distance from Earth's center to the afogee 1. Xa=? So, As at percigee and apogee the velocity of the Satellite will be perbendiculate to radial distance from the Earth's center, do Angulas momentum will be conserved a L = m Vp Up = prava on ta = Op Ve - (2.24 xlof km)x (4.54 kola Va 13.30 kmis) l a = 3:082 x 104 km] SO (