Suppose that the satellite around the earth has an orbit that is 24 KM larger in radius than its previous orbit of 2.25 X 10^5 m. What would its speed be? Is this faster or slower than its previous speed?
Suppose that the satellite around the earth has an orbit that is 24 KM larger in...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is he = 227.0 km, and it is moving with a speed of up = 8.050 km/s. The gravitational constant G equals 6.67 x 10-'1 m² kg---5-2 and the mass of Earth equals 5.972 x 1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what...
A satellite is in orbit around Earth at a height of 120 km above Earth’s surface. Find the orbital speed of the satellite. (Mass of the earth is 6*1024 kg and the radius of Earth is 6371 km)
A satellite is in an elliptic orbit around the Earth. Its speed
at the perigee A is 8500 m/s (Figure 1) .
A) Use conservation of energy to determine its speed at B. The
radius of the Earth is 6380 km.\
B) Use conservation of energy to determine the speed at the
apogee C.
B 13,900 km A с 16,460 km 8230 km 8230 km
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is ho = 207.0 km, and it is moving with a speed of v, = 8.050 kr/s. The gravitational constant G equals 6.67 x 10-11 m² kg-15-2 and the mass of Earth equals 5.972 x 1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what...
Q12-2 Gravitation 1. Find the speed of a satellite in a circular orbit around the Earth with a radius 2.71 times the mean radius of the Earth. (Radius of Earth = 6.37 x 10 km, mass of Earth = 5.98 x 1024 kg, -6.67 x 10" Nm /kg.) (in m/s) 2 V- 5.67 XII VA
A satellite is in a circular orbit around the Earth at an altitude of 3.58 x 100 m. (a) Find the period of the orbit. (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite. m/s toward the center of the Earth
6. [2pt] A satellite is in a circular orbit around the Earth. The period of the satellite is 26.7 hr. Calculate the radius of the satellite's orbit. Data: ME=5.98 x 1024 kg, G = 6.67 x 10-11 Nm²/kg2. Answer: Submit Al Answers 7. [2pt] What is the speed of the satellite in the previous problem? Answer: (Submit All Answers)
A satellite in an elliptical orbit around Earth has a speed of 8202 m/s when it is at perigee, the position in the orbit closest to Earth. At this position, the satellite is 122 km above Earth's surface. Part A How far above the ground is the satellite when it is at apogee, the position in its orbit farthest from Earth? Express your answer with the appropriate units.
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its closest approach to the Earth, its height above the ground is hp = 217.0 km and it is moving with a speed of vp = 8.850 km/s. When the satellite reaches its apogee, at its farthest point from the Earth, what is its height ha above the ground?